High School

Two trains leave towns 708 miles apart at the same time and travel toward each other. One train travels 13 miles per hour slower than the other. If they meet in 4 hours, what is the rate of each train?

Answer :

The distance, rate and time relationship and the distance between the two trains indicates;

The rate of the faster train is 95 mph

The rate of the slower train is 85 mph

What is the rate distance and time relationship?

The steady rate of the motion of an object, r, can be obtained from the ratio of the distance traveled, d, to the duration of travel, t. r = d/t.

Let r represent the rate of the faster train, therefore;

The rate of the slower train = r - 13

The two trains are traveling together, therefore, we get;

The combined rate = r + r - 13 = 2·r - 13 miles per hour

The duration it takes for the two train to meet = 4 hours

The formula for distance rate and time can be used to find the combined rate of the two trains as follows;

Distance, d = r·t

Where the combined distance traveled by the two trains, d = The distance between the towns from which the trains depart, which is 708 miles

Therefore; 708 = (2·r - 13) × 4

2·r - 13 = 708/4 = 177

2·r = 177 + 13 = 190

r = 190/2 = 95

The faster of the faster train, r = 95 miles per hour

The rate of the slower train = 95 - 13 = 82 miles per hour

Learn more on distance, rate and time formula here: https://brainly.com/question/4931057

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