High School

Lin and Jada each walk at a steady rate from school to the library. Lin can walk 13 miles in 5 hours, and Jada can walk 25 miles in 10 hours. They each leave school at 3:00 and walk 3 1/4 miles to the library.

What time do they each arrive?

Answer :

Answer:

It will take Lin an hour and 25 minutes at her constant speed, and it will take Jada at her constant speed an hour and 30 minutes.

SO, Lin will arrive at 4:25

and Jada will arrive at 4:30

There is a 5 minute difference in time.

Step-by-step explanation:

From the facts given, Lin can walk 13 miles in 5 hours which when you divide means she can walk 2.6 mph (miles per hour), and Jada can walk 2.5 mph.

To get these answers you divide the current speeds into the total distance

For example, in Lin's case...

3.25 (The 3 and 1/4 mile converted to decimal form)

2.6 (Lin's Average speed per hour)

3.25/2.6=1.25

1.25 (1 hour and 25 minutes)

Final answer:

Lin's speed is 2.6 mph, and Jada's is 2.5 mph. Given the distance they are to travel, Lin takes 1.25 hours to reach, and Jada takes 1.3 hours from 3:00, so Lin arrives at the library at 4:15 and Jada at 4:18.

Explanation:

The subject at hand is understanding speed, distance, and time relationships. Let's first calculate Lin's and Jada's speeds. Speed is calculated by dividing the distance by the time, so Lin's speed is 13 miles / 5 hours = 2.6 miles per hour, and Jada's speed is 25 miles / 10 hours = 2.5 miles per hour. Lin and Jada are each walking 3 1/4 miles to the library, so we calculate their respective times by dividing the distance by their speeds. For Lin, it takes 3.25 miles / 2.6 mph = 1.25 hours, and for Jada, it's 3.25 miles / 2.5 mph = 1.3 hours. Since each hour contains 60 minutes, Lin's time translates to 1 hour and 15 minutes, and Jada's to 1 hour and 18 minutes. If they left school at 3:00, then Lin arrives around 4:15 and Jada around 4:18.

Learn more about Speed, Distance, and Time Relationships here:

https://brainly.com/question/33629740

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