High School

A snail traveling at 13 inches per hour leaves the tree stump at 6:00 am and heads for the pond. One hour later, a frog hops out of the pond and heads for the tree stump at 40 inches per hour. If the pond and the stump are 20 feet apart, at what time does the frog pass the snail?

Answer :

Step-by-step explanation:

The closing speed between the two critters is

13 in/hr + 40 inches / hr = 53 inches per hour

at 53 inches per hour, the 20 ft ( which is 240 inches...then less the 13 inches the snail has already crawled ) ) will be travelled in

( 240-13) inches / 53 inches/hr = ~4 hour 17 minutes after the frog starts

which would be 7 AM + 4 :17 = 11:17 AM

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