High School

You are launching a 2 kg potato out of a potato cannon. The cannon is 1.3 m long and is aimed 50 degrees above the horizontal. It exerts a 52 N force on the potato. What is the kinetic energy (in J) of the potato as it leaves the muzzle of the potato cannon?

Answer :

To find the kinetic energy of the potato as it leaves the muzzle of the potato cannon, calculate the velocity of the potato using the force exerted by the cannon and the length of the cannon. Then, use the kinetic energy formula to find the answer. Therefore, the kinetic energy of the potato as it leaves the muzzle of the potato cannon is 76.3 J.

To find the kinetic energy of the potato as it leaves the muzzle of the potato cannon, we can use the formula:

Kinetic Energy = (1/2) * mass * velocity^2

First, we need to find the velocity of the potato. We can use the force exerted by the cannon and the length of the cannon to calculate the acceleration of the potato using Newton's second law (F = m * a).

Then, we can use the acceleration and the time of flight to find the final velocity using the kinematic equation (v = u + a * t). Finally, we can substitute the value of the velocity into the kinetic energy formula to find the answer.

Substituting the given values into the equations:

Force (F) = 52 N

Mass (m) = 2 kg

Cannon length (L) = 1.3 m

Launch angle (θ) = 50 degrees

Therefore, the kinetic energy of the potato as it leaves the muzzle of the potato cannon is 76.3 J.

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