High School

Two buses leave towns 1602 kilometers apart at the same time and travel toward each other. One bus travels 13 km/h slower than the other. If they meet in 6 hours, what is the rate of each bus?

Answer :

The speed of the first bus is 140 km/h, and the second bus's speed (13 km/h slower) is 140 - 13 = 127 km/h. Hence, the rate of each bus is 140 km/h and 127 km/h, respectively.

Let's assume that the speed of one bus is x km/h. Since the other bus is traveling 13 km/h slower, its speed will be (x - 13) km/h.

When two objects are moving towards each other, their combined distance covered is equal to the sum of their individual distances. In this case, the total distance covered by both buses is 1602 kilometers.

We can set up the equation as:

Distance = Speed * Time

For the first bus:

Distance covered by the first bus = Speed of the first bus * Time

Distance covered by the first bus = x km/h * 6 hours

For the second bus:

Distance covered by the second bus = Speed of the second bus * Time

Distance covered by the second bus = (x - 13) km/h * 6 hours

Since the total distance covered by both buses is 1602 kilometers, we can set up the equation:

x km/h * 6 hours + (x - 13) km/h * 6 hours = 1602 kilometers

Simplifying the equation:

6x + 6(x - 13) = 1602

6x + 6x - 78 = 1602

12x - 78 = 1602

12x = 1680

x = 140

Therefore, the speed of the first bus is 140 km/h, and the speed of the second bus (which is 13 km/h slower) is 140 - 13 = 127 km/h.

Hence, the rate of each bus is 140 km/h and 127 km/h, respectively.

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