Answer :
The amount of current that the good battery alone can drive through the starter motor depends on the specific battery and starter motor used, but it is typically around 100-200 amps. Therefore, the current passes through the dead battery in the opposite direction of its normal operation.
The dead battery alone is not able to drive any current through the starter motor because its internal resistance is too high.
With the jumper cables attached, the current passing through the starter motor is the sum of the current provided by both batteries. Assuming both batteries are fully charged and in good condition, the total current could be up to 400 amps or more.
With the jumper cables attached, the dead battery will receive some of the current from the good battery, but the amount depends on the resistance of the dead battery. Assuming the resistance is not too high, the dead battery could receive up to several hundred amps of current.
With the jumper cables attached, current flows from the good battery through the jumper cables, through the dead battery, and then back through the other jumper cable to the starter motor.
1. How much current could the good battery alone drive through the starter motor?
Assuming the good battery has a voltage of 12 V, and the starter motor has a resistance (R_motor), you can use Ohm's Law to find the current:
I = V / R_motor
where I is the current, V is the voltage, and R_motor is the resistance of the starter motor.
2. How much current is the dead battery alone able to drive through the starter motor?
Since the dead battery has a high internal resistance (R_dead_battery) due to chemical reactions, its voltage drops, and it cannot provide sufficient current. We can still use Ohm's Law to calculate the current:
I = V / (R_motor + R_dead_battery)
3. With the jumper cables attached, how much current passes through the starter motor?
When the jumper cables connect the good battery to the dead battery and the starter motor, the total resistance in the circuit is reduced. Let's assume the good battery's internal resistance is R_good_battery, and the resistance of the jumper cables is negligible. Now, the equivalent resistance is given by:
R_eq = (R_good_battery * R_dead_battery) / (R_good_battery + R_dead_battery)
So, the current through the starter motor with jumper cables is:
I = V / (R_motor + R_eq)
4. With the jumper cables attached, how much current passes through the dead battery?
The current passing through the dead battery can be found using Kirchhoff's Current Law, which states that the sum of currents entering a junction equals the sum of currents leaving the junction. Since the dead battery is connected in parallel with the good battery, the current passing through the dead battery is the same as the current passing through the good battery.
5. With the jumper cables attached, in which direction current passes through the dead battery?
Since the good battery is providing current to start the engine and charge the dead battery, the current will flow from the good battery to the dead battery, in the direction opposite to the current flow when the dead battery was functioning normally.
Remember to express all current values in Amperes (A) as the appropriate units.
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