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An automotive battery has an open-circuit voltage of 12.6 V and supplies 100 A when a 0.1-Ω resistance is connected across the battery terminals.

1. Draw the Thévenin and Norton equivalent circuits, including values for the circuit parameters.
2. What current can this battery deliver to a short circuit?
3. Considering that the energy stored in the battery remains constant under open-circuit conditions, which of these equivalent circuits seems more realistic? Explain.

Answer :

The Thévenin and Norton equivalent circuits for the automotive battery are shown below. The Thévenin equivalent circuit has a voltage source of 12.6 V and a resistance of 0.1 Ω in series, while the Norton equivalent circuit has a current source of 100 A and a resistance of 0.1 Ω in parallel.

Thévenin Equivalent Circuit:
```
+---12.6 V---+
| |
| R = 0.1 Ω
| |
+------------+
```

Norton Equivalent Circuit:
```
+---100 A---+
| |
R = 0.1 Ω |
| |
+-----------+
```

The current that the battery can deliver to a short circuit is given by the short-circuit current, which is equal to the open-circuit voltage divided by the internal resistance. Therefore, the short-circuit current is:
Isc = Voc / R = 12.6 V / 0.1 Ω = 126 A
Considering that the energy stored in the battery remains constant under open-circuit conditions, the Thévenin equivalent circuit seems more realistic. This is because the Thévenin equivalent circuit has a voltage source that maintains a constant voltage across the open circuit, while the Norton equivalent circuit has a current source that would deliver an infinite amount of current to an open circuit, which is not realistic.

Read more abaut Norton: https://brainly.com/question/15848796

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