High School

12. A product has failed 4 times over the last 500 hours. What is its mean time between failures (MTBF)?

A. 0.002 hours
B. 0.008 hours
C. 125 hours
D. 500 hours

13. A product has an MTBF of 200 hours and an MTTR of 10 hours. What is its system availability?

A. 0.048
B. 0.050
C. 0.952
D. 1.05

Answer :

12. The mean time between failures is 125 hours. Option C is the correct answer.

13. Its system availability is 0.952. Option C is the correct answer.

Mean Time Between Failures (MTBF) is calculated by dividing the total operating time by the number of failures. In this case, the product failed 4 times over 500 hours.

MTBF = Total Operating Time / Number of Failures

MTBF = 500 hours / 4 failures

MTBF = 125 hours

So, the correct answer is c) 125 hours.

System availability (A) can be calculated using the following formula:

Availability (A) = MTBF / (MTBF + MTTR)

Given MTBF = 200 hours and MTTR = 10 hours:

A = 200 / (200 + 10)

A = 200 / 210

A ≈ 0.952

So, the correct answer is c) 0.952.

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Final answer:

The mean time between failures (MTBF) of the product is 125 hours.

Explanation:

To calculate the Mean Time Between Failures (MTBF), we divide the total operating time by the number of failures. In this case, the product has failed 4 times over the last 500 hours.

MTBF = Total Operating Time / Number of Failures

MTBF = 500 hours / 4

MTBF = 125 hours

Therefore, the mean time between failures (MTBF) of the product is 125 hours.

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