Independent Events In Probability Calculation And Examples

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In the realm of probability theory, understanding the concept of independent events is crucial. Independent events are events where the occurrence of one does not affect the probability of the other occurring. This article will delve deep into this concept, exploring the conditions that define independent events and providing a comprehensive explanation of how to determine if two events are indeed independent. We will address the question: If P(A)=0.60P(A) = 0.60 and P(B)=0.20P(B) = 0.20, under what condition are events A and B independent? To answer this, we will thoroughly examine the mathematical principles and formulas involved. Before diving into the solution, let's first clarify the fundamental concepts of probability and independence.

Probability Basics: A Quick Recap

Before we tackle the problem at hand, let's recap some probability basics. The probability of an event, denoted as P(E)P(E), is a number between 0 and 1, inclusive, that expresses the likelihood of the event E occurring. A probability of 0 indicates that the event is impossible, while a probability of 1 indicates that the event is certain to occur. For instance, if we flip a fair coin, the probability of getting heads is 0.5, and the probability of getting tails is also 0.5. These probabilities are based on the sample space, which is the set of all possible outcomes of a random experiment. In the coin flip example, the sample space consists of two outcomes: heads and tails.

Compound events involve the combination of two or more events. The probability of the union of two events, P(AextorB)P(A ext{ or } B), represents the probability that either event A or event B (or both) occurs. The probability of the intersection of two events, P(AextandB)P(A ext{ and } B), represents the probability that both event A and event B occur simultaneously. These probabilities are interconnected through the addition rule of probability, which states:

P(AextorB)=P(A)+P(B)βˆ’P(AextandB)P(A ext{ or } B) = P(A) + P(B) - P(A ext{ and } B)

This formula is essential for calculating the probability of either event happening, taking into account the possibility of both events occurring together. Now, let's move on to the core concept of independent events.

Defining Independent Events: The Key Condition

Two events, A and B, are considered independent if the occurrence of one does not influence the probability of the other. Mathematically, this independence is defined by the following condition:

P(AextandB)=P(A)imesP(B)P(A ext{ and } B) = P(A) imes P(B)

This equation states that the probability of both A and B occurring is equal to the product of their individual probabilities. This is a crucial concept for understanding probabilistic relationships and is the cornerstone for solving the problem we've presented. To further illustrate, consider two independent coin flips. The outcome of the first flip has no impact on the outcome of the second flip. Therefore, the probability of getting heads on both flips is the product of the probability of getting heads on each individual flip, which is 0.5imes0.5=0.250.5 imes 0.5 = 0.25.

However, it's also important to understand what dependent events are. Events are dependent if the occurrence of one event does affect the probability of the other. For example, drawing cards from a deck without replacement creates dependent events because each card drawn changes the composition of the remaining deck and therefore alters the probabilities of subsequent draws. Identifying whether events are independent or dependent is crucial for selecting the correct probability formulas and calculations.

Solving the Problem: Applying the Independence Condition

Now, let's apply the concept of independent events to solve the given problem. We are given P(A)=0.60P(A) = 0.60 and P(B)=0.20P(B) = 0.20. We need to determine the condition under which events A and B are independent. According to the independence condition:

P(AextandB)=P(A)imesP(B)P(A ext{ and } B) = P(A) imes P(B)

Substituting the given values, we have:

P(AextandB)=0.60imes0.20=0.12P(A ext{ and } B) = 0.60 imes 0.20 = 0.12

This calculation shows that for events A and B to be independent, the probability of both A and B occurring must be 0.12. Let's analyze the provided options in light of this result.

Analyzing the Options: Which Condition Holds True?

We have four options to consider:

A. P(AextorB)=0.12P(A ext{ or } B) = 0.12 B. P(AextorB)=0.80P(A ext{ or } B) = 0.80 C. P(AextandB)=0.12P(A ext{ and } B) = 0.12 D. P(AextandB)=0P(A ext{ and } B) = 0

Option A states that P(AextorB)=0.12P(A ext{ or } B) = 0.12. This option is incorrect because the probability of the union of events (P(AextorB)P(A ext{ or } B)) is not the direct indicator of independence. Independence is determined by the relationship between the probabilities of the individual events and their intersection (P(AextandB)P(A ext{ and } B)).

Option B states that P(AextorB)=0.80P(A ext{ or } B) = 0.80. To verify this, we can use the addition rule of probability:

P(AextorB)=P(A)+P(B)βˆ’P(AextandB)P(A ext{ or } B) = P(A) + P(B) - P(A ext{ and } B)

If A and B are independent, then P(AextandB)=0.12P(A ext{ and } B) = 0.12. Substituting the given values:

P(AextorB)=0.60+0.20βˆ’0.12=0.68P(A ext{ or } B) = 0.60 + 0.20 - 0.12 = 0.68

Thus, P(AextorB)P(A ext{ or } B) should be 0.68 for independent events, making option B incorrect.

Option C states that P(AextandB)=0.12P(A ext{ and } B) = 0.12. As we calculated earlier, this is the exact condition required for A and B to be independent events. The probability of both A and B occurring is the product of their individual probabilities, satisfying the independence condition.

Option D states that P(AextandB)=0P(A ext{ and } B) = 0. This would imply that events A and B are mutually exclusive, meaning they cannot occur at the same time. However, for independent events with non-zero probabilities, their intersection cannot be zero. Therefore, this option is incorrect.

Conclusion: The Definitive Answer

In conclusion, given P(A)=0.60P(A) = 0.60 and P(B)=0.20P(B) = 0.20, events A and B are independent if P(AextandB)=0.12P(A ext{ and } B) = 0.12. This corresponds to option C. The key to determining independence lies in verifying that the probability of the intersection of the events is equal to the product of their individual probabilities. Understanding this concept is vital for solving a wide range of probability problems and for making informed decisions in various real-world scenarios involving uncertainty. By carefully applying the definition of independence and utilizing the appropriate formulas, we can accurately assess the relationships between events and make meaningful predictions about their likelihood.

This exploration of independent events highlights the elegance and power of probability theory in describing and predicting random phenomena. By grasping these fundamental concepts, we equip ourselves with the tools to analyze complex situations and make sound judgments based on probabilistic reasoning.